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2.08x^2-416x+3952=0
a = 2.08; b = -416; c = +3952;
Δ = b2-4ac
Δ = -4162-4·2.08·3952
Δ = 140175.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-416)-\sqrt{140175.36}}{2*2.08}=\frac{416-\sqrt{140175.36}}{4.16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-416)+\sqrt{140175.36}}{2*2.08}=\frac{416+\sqrt{140175.36}}{4.16} $
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